6?2(1+2)= ?

[Ragnar]

I say its 1, people in my work says its 9. IDK kickback you tell me.

[CavySlaveJambo]

12 (if it is a divide sign)

[systemx]

six

[Victorian]

that would be 9 then.

[Hansel]

9

[Dean Winchester]

I say its 1, people in my work says its 9. IDK kickback you tell me.

 

I'm wrong

[davemclaren]

multiplication and division are commutative not associative. 9.

[Moriarty]

9 isnt it?

 

6?2(1+2)= x

3(1+2)= x

3(3)= x

9=x

[Ragnar]

Theres a similar equation on a different forum where the thread got around 85 pages of people arguing about the answers luls.

[Ragnar]

6?2(1+2)

 

6?2(3)

 

6?6

 

1

[Maple Leaf]

I typed the formula into Google. It says the answer is 9.

[Dean Winchester]

6?2(1+2)

 

6?2(3)

 

6?6

 

1

 

Made the same mistake as you when I first done it.

 

It's 6/2(1+2)

6/2(3)

3(3)

9

[davemclaren]

I typed the formula into Google. It says the answer is 9.

 

[Victorian]

6?2(1+2)

 

6?2(3)

 

6?6

 

1

 

no. the sum within the bracket is separate and is multiplied by the sum outside the bracket.

[Rick Grimes]

6?2(1+2)

 

6?2(3)

 

6?6

 

1

 

 

this, based on the old 'Bless My Dear Aunt Sally' rule

[Ragnar]

this, based on the old 'Bless My Dear Aunt Sally' rule

 

So it is 1?

[Maple Leaf]

 

I thought the answer was 1. I'm not gonna argue with Google.

[Sierra Delta]

It's 1 I think, using the BODMAS rule.

[Bigsmak]

Answer is 1... always do brackets first. That's the rules.

 

For it to be 9 you would need

 

(6/2)(1+2)

[Commander Harris]

the simple answer is that where ambiguity exists, use parentheses!

[Victorian]

85 pages i reckon. six bans / two suicides (one premature birth + two divorces) = ?

[Rick Grimes]

So it is 1?

 

 

I'd say so

 

http://en.wikipedia.org/wiki/Order_of_operations#The_standard_order_of_operations

 

1 + 2 is definitely done first according to the above. I guess you could debate over whether the 2 * 3 or 6 / 2 is done first but as the multiplication is being done on the product of the sum in the brackets I'd resolve that first.

[Dave Spacey]

I don't understand how people get 9

 

I get 1

[Dean Winchester]

I'd say so

 

http://en.wikipedia.org/wiki/Order_of_operations#The_standard_order_of_operations

 

1 + 2 is definitely done first according to the above. I guess you could debate over whether the 2 * 3 or 6 / 2 is done first but as the multiplication is being done on the product of the sum in the brackets I'd resolve that first.

Isn't multiplication and division treated equally therefore you go for the one leftmost in this case division and therefore end up with 9...

[Hansel]

If I get an equation with

 

3(1+2) I always assume that you multiply.

 

I'm no mathematical genius though.

[I P Knightley]

Brackets

Exponentials (powers)

Division

Multiplication

Addition

Subtraction

 

 

The answer's 1.

 

Bracket first and all that goes with it (3 x 2); then divide.

 

No fee.

 

My pleasure.

[Rick Grimes]

Isn't multiplication and division treated equally therefore you go for the one leftmost in this case division and therefore end up with 9...

 

that's where you can argue it either way. as the multiplication is being done directly on the brackets I'm counting that as part of that operation.

 

if it was 6/2*(1+2) then you'd definitely be right, as is I'm not sure.

[Ragnar]

200 pages

5 bans

1 suicide

[shaun.lawson]

I don't understand how people get 9

 

I get 1

 

Nine's the answer most people arrive at - because not realising the difference it makes, they do the 1+2 first. That's 3 - then they go on to multiply the sum of 6/2 (in other words, 3) by the 3 they already have, which makes nine.

 

As others have said though, the answer's 1.

[Moriarty]

Nine's the answer most people arrive at - because not realising the difference it makes, they do the 1+2 first. That's 3 - then they go on to multiply the sum of 6/2 (in other words, 3) by the 3 they already have, which makes nine.

 

As others have said though, the answer's 1.

 

google says its 9.

 

Im going with google.

[Dean Winchester]

that's where you can argue it either way. as the multiplication is being done directly on the brackets I'm counting that as part of that operation.

 

if it was 6/2*(1+2) then you'd definitely be right, as is I'm not sure.

 

But surely

6/2*(1+2)

is equivalent to

6/2(1+2)

 

Just as

3*(4)

is equivalent to

3(4)

 

Certainly how I got taught it anyway.

[Dave Spacey]

Nine's the answer most people arrive at - because not realising the difference it makes, they do the 1+2 first. That's 3 - then they go on to multiply the sum of 6/2 (in other words, 3) by the 3 they already have, which makes nine.

 

As others have said though, the answer's 1.

 

Ah, that makes more sense, thanks Shaun.

 

So they've went

 

6/2(1+2)

to (6/2)(3)

 

How do you do a division sign on the keyboard?

[shaun.lawson]

google says its 9.

 

Im going with google.

 

For the only time in my entire life, I'm not.

[Hansel]

The answer is 9

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

Even if it's not

[Rick Grimes]

But surely

6/2*(1+2)

is equivalent to

6/2(1+2)

 

Just as

3*(4)

is equivalent to

3(4)

 

Certainly how I got taught it anyway.

 

 

the way I wrote it out probably confuses the issue but was just to illustrate the difference in how we're reading it.

 

Shaun's explanation is better as it stresses that the sum inside the brackets is only part of the overall operation that's being done at that stage & hence before the division in the overall problem.

[Dean Winchester]

The answer is 9

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

Even if it's not

 

But it is

[Alan_R]

its 100% 9

[The Brow]

Did nobody do first year maths?

 

Brackets

Of

Multiply

Division

Add

Subtract

 

Follow the rules people.

 

6\2(1+2)

6\2(3)

6\6

1

 

The answer's 1. Anyone who says anything else needs to go back to school.

[York Ninja]

Brackets

Over

Division

Multiplication

Addition

Subtraction

 

This makes the answer 1

 

Ninja

[shaun.lawson]

Did nobody do first year maths?

 

Brackets

Of

Division

Multiply

Add

Subtract

 

Follow the rules people.

 

6\2(1+2)

6\2(3)

6\6

1

 

The answer's 1. Anyone who says anything else needs to go back to school.

 

Nailed it. Perfect explanation.

[Hansel]

I would have understood all this about 12 years ago, but I haven't found any use for equations since I left school.

As the old saying goes, "equations, what a load of crap"!

[Victorian]

:omg!: check this oot.

 

http://www.thestudentroom.co.uk/showthread.php?t=1621621

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

it's 9 by the way.

[Dean Winchester]

the way I wrote it out probably confuses the issue but was just to illustrate the difference in how we're reading it.

 

Shaun's explanation is better as it stresses that the sum inside the brackets is only part of the overall operation that's being done at that stage & hence before the division in the overall problem.

 

Talk me through your working out of it because from the way I see it using BODMAS we check if theres brackets first and do

6/2(1+2) = 6/2(3)

we then go back to the start and left to right and using bodmas again we use division on 6/2(3) to get 3 seeing as the brackets have already been dealt with

we're then left with 3(3) which is equivalent to 3*(3) and get 9.

 

My understanding of the brackets part was you dealt with the operation inside the bracket, the just because there was a value outside it you don't go from 6/2(3) (There is no operation inside the bracket here, just a value) to 6/6

[shaun.lawson]

Talk me through your working out of it because from the way I see it using BODMAS we check if theres brackets first and do

6/2(1+2) = 6/2(3)

we then go back to the start and left to right and using bodmas again we use division on 6/2(3) to get 3 seeing as the brackets have already been dealt with

we're then left with 3(3) which is equivalent to 3*(3) and get 9.

 

My understanding of the brackets part was you dealt with the operation inside the bracket, the just because there was a value outside it you don't go from 6/2(3) (There is no operation inside the bracket here, just a value) to 6/6

 

You're forgetting something. 2(3) means two times three - which is what turns it into six divided by six.

 

It's all there in the equation. You just have to see it.

[davemclaren]

Talk me through your working out of it because from the way I see it using BODMAS we check if theres brackets first and do

6/2(1+2) = 6/2(3)

we then go back to the start and left to right and using bodmas again we use division on 6/2(3) to get 3 seeing as the brackets have already been dealt with

we're then left with 3(3) which is equivalent to 3*(3) and get 9.

 

My understanding of the brackets part was you dealt with the operation inside the bracket, the just because there was a value outside it you don't go from 6/2(3) (There is no operation inside the bracket here, just a value) to 6/6

 

I'm with you.

[Dean Winchester]

You're forgetting something. 2(3) means two times three - which is what turns it into six divided by six.

 

It's all there in the equation. You just have to see it.

I know what 2(3) is.

 

But you have 6/2(3).

 

There is no operation inside the brackets therefore the first part of BODMAS at this point is DM and going left to right the first occurence is 6/2.

[Rick Grimes]

Talk me through your working out of it because from the way I see it using BODMAS we check if theres brackets first and do

6/2(1+2) = 6/2(3)

we then go back to the start and left to right and using bodmas again we use division on 6/2(3) to get 3 seeing as the brackets have already been dealt with

we're then left with 3(3) which is equivalent to 3*(3) and get 9.

 

My understanding of the brackets part was you dealt with the operation inside the bracket, the just because there was a value outside it you don't go from 6/2(3) (There is no operation inside the bracket here, just a value) to 6/6

 

 

the difference in how we're reading it is you stopping taking brackets as the most important once you've resolved what's inside them. I'm taking the operation of multiplying on the brackets as more important than the division as the bracket still exists - until you fully resolve the brackets, inside & out, then they are paramount.

 

IMO

[Hansel]

 

[The Brow]

I know what 2(3) is.

 

But you have 6/2(3).

 

There is no operation inside the brackets therefore the first part of BODMAS at this point is DM and going left to right the first occurence is 6/2.

 

The actual correct theory is BOMDAS. Some folk use BODMAS but the actual proper way is BOMDAS.

 

This means you get

 

(Multiply first) so the problem becomes

 

6 divided by 2x3

 

which is 6 divided by 6

 

which is 1

[Dean Winchester]

the difference in how we're reading it is you stopping taking brackets as the most important once you've resolved what's inside them. I'm taking the operation of multiplying on the brackets as more important than the division as the bracket still exists - until you fully resolve the brackets, inside & out, then they are paramount.

 

IMO

 

Put (3) or (1+2) into a calculator and see what you get